Description.
Here is the circuit diagram of a simple
100 watt inverter using IC CD4047 and MOSFET IRF540. The circuit is
simple low cost and can be even assembled on a veroboard.
CD 4047 is a low power CMOS
astable/monostable multivibrator IC. Here it is wired as an astable
multivibrator producing two pulse trains of 0.01s which are 180 degree
out of phase at the pins 10 and 11 of the IC. Pin 10 is connected to the
gate of Q1 and pin 11 is connected to the gate of Q2. Resistors R3 and
R4 prevents the loading of the IC by the respective MOSFETs. When pin 10
is high Q1 conducts and current flows through the upper half of the
transformer primary which accounts for the positive half of the output
AC voltage. When pin 11 is high Q2 conducts and current flows through
the lower half of the transformer primary in opposite direction and it
accounts for the negative half of the output AC voltage.
Circuit diagram.
- B1 can be a 12V/ 6Ah lead acid battery.
- Q1 and Q2 must be fitted to a proper heat sink.
- T1 can be a 9-0-9 V primary, 230V secondary, 150VA transformer .
- Do not expect much from this circuit. The is very simple one suitable for low grade applications.
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